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anonymous

  • 5 years ago

A ball is thrown upward from a 100-foot tall building with an initial velocity of 14 feet per second. Its height s(t) is given by the function s(t) = -16t squared + 14t +100. Find the interval of time for which the ball is greater than 103 feet.

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  1. anonymous
    • 5 years ago
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    \[t0 = 3/8, t1 = 0.5\]

  2. anonymous
    • 5 years ago
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    just solve for the height equation when it's greater than 103ft, that's -16t^2+14t+100>103 ---> 3/8<t<1/2, as locorider said

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