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bri
 5 years ago
the function f(x) = e^x  x^3 has how many critical points?
bri
 5 years ago
the function f(x) = e^x  x^3 has how many critical points?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What is critical point? o.o

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[f \prime(x)=e^x3x^2\] solve f(x)=0 for all x's.. e^x3x^2=0 is hard to be solved manually. is this a first course in calculus?

bri
 5 years ago
Best ResponseYou've already chosen the best response.0i know that is what you have to do, i just dont want to do it.

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0let the computer work for you ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol.. are you sure of the problem you gave anyway? is it x^3?

bri
 5 years ago
Best ResponseYou've already chosen the best response.0i typed it correctly. it is e raised to the x minus x raised to the third.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0since you just want to the answer, I used a software program and found that it has three critical points.

bri
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, i just figured it out because i got tired of waiting, thanks though

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's not really that hard.. \[e^x  3x^2 = 0 \rightarrow e^x = 3x^2 \rightarrow x = ln{3} + 2ln{x}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then just graph both those functions and find where they intersect.

bri
 5 years ago
Best ResponseYou've already chosen the best response.0wow, polpak, arent you impressive

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, but not because of this.. ;p

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah right I didn't think of graphing method.. but I think it's easier to graph e^x=3x^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I like the other graph cause e^x grows so fast it's hard to see where they intersect, y=x and lnx are much closer to the origin by comparison.
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