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anonymous

  • 5 years ago

What is the factorization of the polynomial graphed below? Assume it has no constant factor

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  1. anonymous
    • 5 years ago
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  2. anonymous
    • 5 years ago
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    Please use a 'standard' image format.

  3. myininaya
    • 5 years ago
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    I can't oopen it

  4. anonymous
    • 5 years ago
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  5. anonymous
    • 5 years ago
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    there we go

  6. myininaya
    • 5 years ago
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    this graph has a shape of x^3 so it is degree 3 polynomial having x-intercepts at x=2,x=3,x=4 which implies you have the factors x-2 and x-3 and x-4 so the polynomial is P(x)=(x-2)(x-3)(x-4)

  7. anonymous
    • 5 years ago
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    should i put the p(x) in as my answer

  8. myininaya
    • 5 years ago
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    you can name the function whatever you want unless the book or teacher ask you to name it something else

  9. anonymous
    • 5 years ago
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    ? im just asking do i need to put p(x) in as part of my answer

  10. anonymous
    • 5 years ago
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    can you explain how to do this please how did you get the answer

  11. myininaya
    • 5 years ago
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    this graph has degree 3 and has x intercepts x=2,x=3,x=4 correct?

  12. anonymous
    • 5 years ago
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    yes

  13. myininaya
    • 5 years ago
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    if x=2 is an x intercept, then x-2 is a factor of our function. if x=3 is an x intercept, then x-3 is a factor of our function. if x=4 is an x intercept, then x-4 is a factor of our function.

  14. anonymous
    • 5 years ago
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    The graph has 3 x intercepts. Therefore it has 3 distinct roots and can be represented as a product of 3 factors: (x-a)(x-b)(x-c) Where a, b, and c correspond to the 3 x values for which the graph is at y=0

  15. anonymous
    • 5 years ago
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    ok but what does all that mean

  16. anonymous
    • 5 years ago
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    ok polpak but how do i get my answer then

  17. myininaya
    • 5 years ago
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    a,b,c are the x intercepts just plug them in to his expression for f(x)

  18. anonymous
    • 5 years ago
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    ok ill try

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