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anonymous

  • 5 years ago

Note that in an isosceles triangle, two angles have the same measure and the sum of all three angle measures is 180 degrees. Set up and equation and solve: Determine the measure (in degrees) of the third angle in an isosceles triangle, if the third angle is 10 more than one-half of either of the equal measure angles.

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  1. anonymous
    • 5 years ago
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    since two angles are equal let's say they both equal x. ok? so angle 1 =x and angle 2 =x since angle 1 and 2 are the same. not it says the third angle is 10 more than one half of either one. so third angle = 10 + (x/2) so now you can add all the three angles up and make them equal to 180 and you will find your answer. so x + x + 10 + (x/2) = 2x + 10 + (x/2) = 5x/2 + 10 = 180 so 5x/2 = 170 5x = 340 x = 340/5 x = 68

  2. anonymous
    • 5 years ago
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    so angle 1 = 68 angle 2 = 68 angle 3 = 10+(68/2) = 10 + 34 = 44 and if you add all those up they will equal to 180

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