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anonymous

  • 5 years ago

if O is the center of the cirlce ,BC =10 and OC=13 find OA.

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  1. anonymous
    • 5 years ago
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    upload the picture you had before please

  2. anonymous
    • 5 years ago
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  3. anonymous
    • 5 years ago
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    ok so from the image since OA goes straight down and BC is perpendicular to OA then we know that OA cuts exactly half the length of BC. so BC length = 10 --> 10/2 = 5 and we know OC = 13 so we can use pythagorean's theorem to find OA. OA^2 + BC^2 = OC^2 so OA^2 + 5^2 = 13^2 OA^2 = 325 OA = 18.0278

  4. anonymous
    • 5 years ago
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    OA^2 = 144

  5. anonymous
    • 5 years ago
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    so what theorem would you use to find what an arc measures?

  6. myininaya
    • 5 years ago
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    mouse is correct 169-25=144

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