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so r*r*r*r*r*r*r*r*r
t*t*t*t*t*t*t*t*t

yes so 5r^9t^9?

yes.

yayyy, can you explain the FOIL method to me?

Sure. You know that
a(b+c) = ab + ac
Right?

yes so like (3x-6)(x-12)
= 4x+18

That's jumping ahead, and not quite correct. Lets back up a step.

haha ok sorry

4(x + 3) = ?

4x+12?

Right.
But we know that 4 is 3 + 1, so we should get the same thing if we rewrite it as
(3+1)(x+3)

And then we distribute again..
\[(3+1)x+(3+1)3 = 3x + 1x + 9 + 3\]

\[ = 4x+12\]

sorry had to step away for a moment

=4x+12?

+bd

i have like 5 sections and the first says use the foil and the rest just says find the product

oh okay im going to work a problem really quick can you check my answer?

yep

(3x-6)(x-12)
4x+3x-12-6x+18

Afraid not.
(3x-6)(x-12)
Multiply the
F irst two terms (3x and x)
3x * x = ?

4x

Nope.
4x = 3x + x

3x^2

Correct.
Now the
I nner two terms (-6 and x)
-6 * x = ?

-6x

Now the
O uter two terms(-6 and -12)
-6 * -12 = ?

72

Blah! Those are not the outer terms, they're the Last terms. Sorry.

Now the
O uter two terms(3x and -12)
3x * -12 = ?

is it -36x? or does it say the same since they are not like terms?

it is -36x, just like -6 * x was -6x.

You can rearrange the factors of a product.
a*b*c = a*c*b = b*c*a = c*a*b = ... etc

so now i have:
3x^2-6x^36x+72?

yes, except that it's -6x-36x, not -6x^36x but I think that was a typo.

yes sorry so now it is 33?

-6-36 = ?

-42

so
-6x-36x = x(-6-36) = ?

x(-42)

So
\[ 3x^2 - 6x - 36x - 72 = ?\]

i thought i had the answer, im never going to get through college :(
3x^2-x(-42)-72

You're really close. The only problem is you left an extra - there.

before 72?

right

everytime i think i get it a new problem comes up and im so lost again

so if you have -6x's and you take away 36x's you'll be at -42x's

yes your right, im just frustrated if i cant get this how am i supposted to get the next two classes