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anonymous
 5 years ago
Please help me,
simplify, leave in exponent form
5(rt)^9
anonymous
 5 years ago
Please help me, simplify, leave in exponent form 5(rt)^9

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Expand, then simplify. Eventually you'll be able to do the simple way, but for now lets keep with the basics.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you want to have someone check your answer please post the answer you got and ask for a check. Just posting the problem makes it appear as though you're not doing the work or understanding the material which makes people tend to not want to continue helping. If you show that you've done it and you just want to be sure you're correct people are more than happy to confirm.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so r*r*r*r*r*r*r*r*r t*t*t*t*t*t*t*t*t

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i still dont understand i get some of the problems but a few of them like this and the last I just cant figure out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's ok. you're doing really well. \[5(rt)^9 = 5(rt)(rt)(rt)(rt)(rt)(rt)(rt)(rt)(rt)\] \[=5rrrrrrrrrttttttttt\] Right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yayyy, can you explain the FOIL method to me?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sure. You know that a(b+c) = ab + ac Right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes so like (3x6)(x12) = 4x+18

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's jumping ahead, and not quite correct. Lets back up a step.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Right. But we know that 4 is 3 + 1, so we should get the same thing if we rewrite it as (3+1)(x+3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So lets take that whole first factor and multiply it by each of the terms in the second factor \[ \rightarrow (3+1)(x+3) = (3+1)x + (3+1)3\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And then we distribute again.. \[(3+1)x+(3+1)3 = 3x + 1x + 9 + 3\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry had to step away for a moment

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So now if we have something like: (a+b)(c+d) we can distribute: \[(a+b)(c+d) = (a+b)c + (a+b)d = ac + bc + ad + bd\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But to make it easy to remember they prefer you to use FOIL which does the same thing, but in a different order.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have like 5 sections and the first says use the foil and the rest just says find the product

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(a+b)(c+d) They take the F irst two terms(a and c) O uter two terms(a and d) I nner two terms (b and c) L ast two terms (b and d) ac + ad + bc + bd Which is the same as what we had, but with a slightly different order.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh okay im going to work a problem really quick can you check my answer?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(3x6)(x12) 4x+3x126x+18

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Afraid not. (3x6)(x12) Multiply the F irst two terms (3x and x) 3x * x = ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Correct. Now the I nner two terms (6 and x) 6 * x = ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now the O uter two terms(6 and 12) 6 * 12 = ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Blah! Those are not the outer terms, they're the Last terms. Sorry.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now the O uter two terms(3x and 12) 3x * 12 = ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it 36x? or does it say the same since they are not like terms?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is 36x, just like 6 * x was 6x.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can rearrange the factors of a product. a*b*c = a*c*b = b*c*a = c*a*b = ... etc

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so now i have: 3x^26x^36x+72?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, except that it's 6x36x, not 6x^36x but I think that was a typo.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes sorry so now it is 33?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so 6x36x = x(636) = ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So \[ 3x^2  6x  36x  72 = ?\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i thought i had the answer, im never going to get through college :( 3x^2x(42)72

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You're really close. The only problem is you left an extra  there.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We said that 6x36x = x(42) which we can rearrange to be 42x So 3x^2 6x 36x  72 = 3x^2 42x  72

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohh man im never going to pass, im sorry you had to take your free time to help me. thank you so much im just having the hardest time

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no you're doing great Think about it like this. If you have 4x's and you subtract 36x's you'll be at 32x's right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0everytime i think i get it a new problem comes up and im so lost again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so if you have 6x's and you take away 36x's you'll be at 42x's

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's ok. New problems should challenge you. Otherwise you'd just be doing things you already know and you wouldn't learn anything.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes your right, im just frustrated if i cant get this how am i supposted to get the next two classes
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