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anonymous

  • 5 years ago

Please help me, simplify, leave in exponent form 5(rt)^9

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  1. anonymous
    • 5 years ago
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    Expand, then simplify. Eventually you'll be able to do the simple way, but for now lets keep with the basics.

  2. anonymous
    • 5 years ago
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    If you want to have someone check your answer please post the answer you got and ask for a check. Just posting the problem makes it appear as though you're not doing the work or understanding the material which makes people tend to not want to continue helping. If you show that you've done it and you just want to be sure you're correct people are more than happy to confirm.

  3. anonymous
    • 5 years ago
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    so r*r*r*r*r*r*r*r*r t*t*t*t*t*t*t*t*t

  4. anonymous
    • 5 years ago
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    i still dont understand i get some of the problems but a few of them like this and the last I just cant figure out

  5. anonymous
    • 5 years ago
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    It's ok. you're doing really well. \[5(rt)^9 = 5(rt)(rt)(rt)(rt)(rt)(rt)(rt)(rt)(rt)\] \[=5rrrrrrrrrttttttttt\] Right?

  6. anonymous
    • 5 years ago
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    yes so 5r^9t^9?

  7. anonymous
    • 5 years ago
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    yes.

  8. anonymous
    • 5 years ago
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    yayyy, can you explain the FOIL method to me?

  9. anonymous
    • 5 years ago
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    Sure. You know that a(b+c) = ab + ac Right?

  10. anonymous
    • 5 years ago
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    yes so like (3x-6)(x-12) = 4x+18

  11. anonymous
    • 5 years ago
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    That's jumping ahead, and not quite correct. Lets back up a step.

  12. anonymous
    • 5 years ago
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    haha ok sorry

  13. anonymous
    • 5 years ago
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    4(x + 3) = ?

  14. anonymous
    • 5 years ago
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    4x+12?

  15. anonymous
    • 5 years ago
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    Right. But we know that 4 is 3 + 1, so we should get the same thing if we rewrite it as (3+1)(x+3)

  16. anonymous
    • 5 years ago
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    So lets take that whole first factor and multiply it by each of the terms in the second factor \[ \rightarrow (3+1)(x+3) = (3+1)x + (3+1)3\]

  17. anonymous
    • 5 years ago
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    And then we distribute again.. \[(3+1)x+(3+1)3 = 3x + 1x + 9 + 3\]

  18. anonymous
    • 5 years ago
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    \[ = 4x+12\]

  19. anonymous
    • 5 years ago
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    sorry had to step away for a moment

  20. anonymous
    • 5 years ago
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    =4x+12?

  21. anonymous
    • 5 years ago
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    So now if we have something like: (a+b)(c+d) we can distribute: \[(a+b)(c+d) = (a+b)c + (a+b)d = ac + bc + ad + bd\]

  22. anonymous
    • 5 years ago
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    But to make it easy to remember they prefer you to use FOIL which does the same thing, but in a different order.

  23. anonymous
    • 5 years ago
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    +bd

  24. anonymous
    • 5 years ago
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    i have like 5 sections and the first says use the foil and the rest just says find the product

  25. anonymous
    • 5 years ago
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    (a+b)(c+d) They take the F irst two terms(a and c) O uter two terms(a and d) I nner two terms (b and c) L ast two terms (b and d) ac + ad + bc + bd Which is the same as what we had, but with a slightly different order.

  26. anonymous
    • 5 years ago
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    oh okay im going to work a problem really quick can you check my answer?

  27. anonymous
    • 5 years ago
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    yep

  28. anonymous
    • 5 years ago
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    (3x-6)(x-12) 4x+3x-12-6x+18

  29. anonymous
    • 5 years ago
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    Afraid not. (3x-6)(x-12) Multiply the F irst two terms (3x and x) 3x * x = ?

  30. anonymous
    • 5 years ago
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    4x

  31. anonymous
    • 5 years ago
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    Nope. 4x = 3x + x

  32. anonymous
    • 5 years ago
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    3x^2

  33. anonymous
    • 5 years ago
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    Correct. Now the I nner two terms (-6 and x) -6 * x = ?

  34. anonymous
    • 5 years ago
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    -6x

  35. anonymous
    • 5 years ago
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    Now the O uter two terms(-6 and -12) -6 * -12 = ?

  36. anonymous
    • 5 years ago
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    72

  37. anonymous
    • 5 years ago
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    Blah! Those are not the outer terms, they're the Last terms. Sorry.

  38. anonymous
    • 5 years ago
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    Now the O uter two terms(3x and -12) 3x * -12 = ?

  39. anonymous
    • 5 years ago
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    is it -36x? or does it say the same since they are not like terms?

  40. anonymous
    • 5 years ago
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    it is -36x, just like -6 * x was -6x.

  41. anonymous
    • 5 years ago
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    You can rearrange the factors of a product. a*b*c = a*c*b = b*c*a = c*a*b = ... etc

  42. anonymous
    • 5 years ago
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    so now i have: 3x^2-6x^36x+72?

  43. anonymous
    • 5 years ago
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    yes, except that it's -6x-36x, not -6x^36x but I think that was a typo.

  44. anonymous
    • 5 years ago
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    yes sorry so now it is 33?

  45. anonymous
    • 5 years ago
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    -6-36 = ?

  46. anonymous
    • 5 years ago
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    -42

  47. anonymous
    • 5 years ago
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    so -6x-36x = x(-6-36) = ?

  48. anonymous
    • 5 years ago
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    x(-42)

  49. anonymous
    • 5 years ago
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    So \[ 3x^2 - 6x - 36x - 72 = ?\]

  50. anonymous
    • 5 years ago
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    i thought i had the answer, im never going to get through college :( 3x^2-x(-42)-72

  51. anonymous
    • 5 years ago
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    You're really close. The only problem is you left an extra - there.

  52. anonymous
    • 5 years ago
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    before 72?

  53. anonymous
    • 5 years ago
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    We said that -6x-36x = x(-42) which we can re-arrange to be -42x So 3x^2 -6x -36x - 72 = 3x^2 -42x - 72

  54. anonymous
    • 5 years ago
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    ohh man im never going to pass, im sorry you had to take your free time to help me. thank you so much im just having the hardest time

  55. anonymous
    • 5 years ago
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    no you're doing great Think about it like this. If you have 4x's and you subtract 36x's you'll be at -32x's right?

  56. anonymous
    • 5 years ago
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    right

  57. anonymous
    • 5 years ago
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    everytime i think i get it a new problem comes up and im so lost again

  58. anonymous
    • 5 years ago
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    so if you have -6x's and you take away 36x's you'll be at -42x's

  59. anonymous
    • 5 years ago
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    That's ok. New problems should challenge you. Otherwise you'd just be doing things you already know and you wouldn't learn anything.

  60. anonymous
    • 5 years ago
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    yes your right, im just frustrated if i cant get this how am i supposted to get the next two classes

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