anonymous
  • anonymous
Please help me, simplify, leave in exponent form 5(rt)^9
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Expand, then simplify. Eventually you'll be able to do the simple way, but for now lets keep with the basics.
anonymous
  • anonymous
If you want to have someone check your answer please post the answer you got and ask for a check. Just posting the problem makes it appear as though you're not doing the work or understanding the material which makes people tend to not want to continue helping. If you show that you've done it and you just want to be sure you're correct people are more than happy to confirm.
anonymous
  • anonymous
so r*r*r*r*r*r*r*r*r t*t*t*t*t*t*t*t*t

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anonymous
  • anonymous
i still dont understand i get some of the problems but a few of them like this and the last I just cant figure out
anonymous
  • anonymous
It's ok. you're doing really well. \[5(rt)^9 = 5(rt)(rt)(rt)(rt)(rt)(rt)(rt)(rt)(rt)\] \[=5rrrrrrrrrttttttttt\] Right?
anonymous
  • anonymous
yes so 5r^9t^9?
anonymous
  • anonymous
yes.
anonymous
  • anonymous
yayyy, can you explain the FOIL method to me?
anonymous
  • anonymous
Sure. You know that a(b+c) = ab + ac Right?
anonymous
  • anonymous
yes so like (3x-6)(x-12) = 4x+18
anonymous
  • anonymous
That's jumping ahead, and not quite correct. Lets back up a step.
anonymous
  • anonymous
haha ok sorry
anonymous
  • anonymous
4(x + 3) = ?
anonymous
  • anonymous
4x+12?
anonymous
  • anonymous
Right. But we know that 4 is 3 + 1, so we should get the same thing if we rewrite it as (3+1)(x+3)
anonymous
  • anonymous
So lets take that whole first factor and multiply it by each of the terms in the second factor \[ \rightarrow (3+1)(x+3) = (3+1)x + (3+1)3\]
anonymous
  • anonymous
And then we distribute again.. \[(3+1)x+(3+1)3 = 3x + 1x + 9 + 3\]
anonymous
  • anonymous
\[ = 4x+12\]
anonymous
  • anonymous
sorry had to step away for a moment
anonymous
  • anonymous
=4x+12?
anonymous
  • anonymous
So now if we have something like: (a+b)(c+d) we can distribute: \[(a+b)(c+d) = (a+b)c + (a+b)d = ac + bc + ad + bd\]
anonymous
  • anonymous
But to make it easy to remember they prefer you to use FOIL which does the same thing, but in a different order.
anonymous
  • anonymous
+bd
anonymous
  • anonymous
i have like 5 sections and the first says use the foil and the rest just says find the product
anonymous
  • anonymous
(a+b)(c+d) They take the F irst two terms(a and c) O uter two terms(a and d) I nner two terms (b and c) L ast two terms (b and d) ac + ad + bc + bd Which is the same as what we had, but with a slightly different order.
anonymous
  • anonymous
oh okay im going to work a problem really quick can you check my answer?
anonymous
  • anonymous
yep
anonymous
  • anonymous
(3x-6)(x-12) 4x+3x-12-6x+18
anonymous
  • anonymous
Afraid not. (3x-6)(x-12) Multiply the F irst two terms (3x and x) 3x * x = ?
anonymous
  • anonymous
4x
anonymous
  • anonymous
Nope. 4x = 3x + x
anonymous
  • anonymous
3x^2
anonymous
  • anonymous
Correct. Now the I nner two terms (-6 and x) -6 * x = ?
anonymous
  • anonymous
-6x
anonymous
  • anonymous
Now the O uter two terms(-6 and -12) -6 * -12 = ?
anonymous
  • anonymous
72
anonymous
  • anonymous
Blah! Those are not the outer terms, they're the Last terms. Sorry.
anonymous
  • anonymous
Now the O uter two terms(3x and -12) 3x * -12 = ?
anonymous
  • anonymous
is it -36x? or does it say the same since they are not like terms?
anonymous
  • anonymous
it is -36x, just like -6 * x was -6x.
anonymous
  • anonymous
You can rearrange the factors of a product. a*b*c = a*c*b = b*c*a = c*a*b = ... etc
anonymous
  • anonymous
so now i have: 3x^2-6x^36x+72?
anonymous
  • anonymous
yes, except that it's -6x-36x, not -6x^36x but I think that was a typo.
anonymous
  • anonymous
yes sorry so now it is 33?
anonymous
  • anonymous
-6-36 = ?
anonymous
  • anonymous
-42
anonymous
  • anonymous
so -6x-36x = x(-6-36) = ?
anonymous
  • anonymous
x(-42)
anonymous
  • anonymous
So \[ 3x^2 - 6x - 36x - 72 = ?\]
anonymous
  • anonymous
i thought i had the answer, im never going to get through college :( 3x^2-x(-42)-72
anonymous
  • anonymous
You're really close. The only problem is you left an extra - there.
anonymous
  • anonymous
before 72?
anonymous
  • anonymous
We said that -6x-36x = x(-42) which we can re-arrange to be -42x So 3x^2 -6x -36x - 72 = 3x^2 -42x - 72
anonymous
  • anonymous
ohh man im never going to pass, im sorry you had to take your free time to help me. thank you so much im just having the hardest time
anonymous
  • anonymous
no you're doing great Think about it like this. If you have 4x's and you subtract 36x's you'll be at -32x's right?
anonymous
  • anonymous
right
anonymous
  • anonymous
everytime i think i get it a new problem comes up and im so lost again
anonymous
  • anonymous
so if you have -6x's and you take away 36x's you'll be at -42x's
anonymous
  • anonymous
That's ok. New problems should challenge you. Otherwise you'd just be doing things you already know and you wouldn't learn anything.
anonymous
  • anonymous
yes your right, im just frustrated if i cant get this how am i supposted to get the next two classes

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