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- anonymous

Anyone here good with linear algebra?

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- anonymous

Anyone here good with linear algebra?

- jamiebookeater

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- anonymous

Yes, what's your question?

- anonymous

Suppose A is an nxn matrix, whose determinant is not equal to zero and which satisfies the following condition: A^2=A. Prove that A must be equal to In, where I is the identity matrix. Cite any theorems/ definitions used.
It'd be a great help if I could get a little "push" or hint.

- anonymous

Are you taking a college course or middle school? If it's a college course, then you're further ahead than I am.

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- anonymous

Sorry, high school*

- anonymous

Jzzkc, linear algebra isn't the same thing as the algebra of linear equations. :P

- anonymous

College course :(

- anonymous

Det =/= 0 <=> There Exists a nxn matrix B s.t AB = I = BA.

- anonymous

=> A^2 = AA = A
=> AAB = AB
=> AI = I
=> A = I

- anonymous

How did you get A62 = AA to become A?

- anonymous

A^2 = A. The matrix satisfies this condition.

- anonymous

and A^2 = AA.

- anonymous

Are you also famliar with span and null space?

- anonymous

Yes I suppose so.

- anonymous

How did you get from the A^2=AA=A step to the step AAB=AB?

- anonymous

I multiplied B, the matrix that has the property AB = I = AB. The Inverse of A.
You could multiply it like this => BAA = BA too if you want.

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