A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
Anyone here good with linear algebra?
anonymous
 5 years ago
Anyone here good with linear algebra?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, what's your question?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Suppose A is an nxn matrix, whose determinant is not equal to zero and which satisfies the following condition: A^2=A. Prove that A must be equal to In, where I is the identity matrix. Cite any theorems/ definitions used. It'd be a great help if I could get a little "push" or hint.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you taking a college course or middle school? If it's a college course, then you're further ahead than I am.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Jzzkc, linear algebra isn't the same thing as the algebra of linear equations. :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Det =/= 0 <=> There Exists a nxn matrix B s.t AB = I = BA.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0=> A^2 = AA = A => AAB = AB => AI = I => A = I

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How did you get A62 = AA to become A?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A^2 = A. The matrix satisfies this condition.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you also famliar with span and null space?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How did you get from the A^2=AA=A step to the step AAB=AB?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I multiplied B, the matrix that has the property AB = I = AB. The Inverse of A. You could multiply it like this => BAA = BA too if you want.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.