anonymous
  • anonymous
where do i go from, 15(5x^2-1)-(x-2)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
What are you trying to do?
anonymous
  • anonymous
factor the polynomial.
anonymous
  • anonymous
egh. I'd start by getting it into the standard polynomial form

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anonymous
  • anonymous
the original is, 75x^3-150x^2-15x+30
anonymous
  • anonymous
Ok, so factor a 15 out of everything.
anonymous
  • anonymous
well i do factor by grouping
anonymous
  • anonymous
I'd start by getting smaller numbers.
anonymous
  • anonymous
well thats why i broke it up into 75x^3-150x^2 abd -15x+30
anonymous
  • anonymous
and*
anonymous
  • anonymous
\[75x^3-150x^2-15x+30\] \[= 15(5x^3 - 10x^2 - x + 2)\]
anonymous
  • anonymous
Then regrouping and pulling a 5x from the first two terms you should have something nice.
anonymous
  • anonymous
that way you would pull out a 75 and get 75x^2(x-2)15(x-2)
anonymous
  • anonymous
so then its (75x^2-15) and (x-2) thenn 15(5x^2+1)(x-2)
anonymous
  • anonymous
\[15(5x^3 - 10x^2 - x + 2) \] \[= 15[5x(x-2) -(x-2)]\] \[= 15(5x-1)(x-2)\]
anonymous
  • anonymous
whoops i meant -1.
anonymous
  • anonymous
so i basically had the right answer right?
anonymous
  • anonymous
Yes.
anonymous
  • anonymous
Mine should be \[15[5x^2(x−2)−(x−2)]\] \[=15(5x^2-1)(x-2)\]
anonymous
  • anonymous
gotcha
anonymous
  • anonymous
alright i will be back in a few with some more

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