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anonymous

  • 5 years ago

where do i go from, 15(5x^2-1)-(x-2)

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  1. anonymous
    • 5 years ago
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    What are you trying to do?

  2. anonymous
    • 5 years ago
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    factor the polynomial.

  3. anonymous
    • 5 years ago
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    egh. I'd start by getting it into the standard polynomial form

  4. anonymous
    • 5 years ago
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    the original is, 75x^3-150x^2-15x+30

  5. anonymous
    • 5 years ago
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    Ok, so factor a 15 out of everything.

  6. anonymous
    • 5 years ago
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    well i do factor by grouping

  7. anonymous
    • 5 years ago
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    I'd start by getting smaller numbers.

  8. anonymous
    • 5 years ago
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    well thats why i broke it up into 75x^3-150x^2 abd -15x+30

  9. anonymous
    • 5 years ago
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    and*

  10. anonymous
    • 5 years ago
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    \[75x^3-150x^2-15x+30\] \[= 15(5x^3 - 10x^2 - x + 2)\]

  11. anonymous
    • 5 years ago
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    Then regrouping and pulling a 5x from the first two terms you should have something nice.

  12. anonymous
    • 5 years ago
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    that way you would pull out a 75 and get 75x^2(x-2)15(x-2)

  13. anonymous
    • 5 years ago
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    so then its (75x^2-15) and (x-2) thenn 15(5x^2+1)(x-2)

  14. anonymous
    • 5 years ago
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    \[15(5x^3 - 10x^2 - x + 2) \] \[= 15[5x(x-2) -(x-2)]\] \[= 15(5x-1)(x-2)\]

  15. anonymous
    • 5 years ago
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    whoops i meant -1.

  16. anonymous
    • 5 years ago
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    so i basically had the right answer right?

  17. anonymous
    • 5 years ago
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    Yes.

  18. anonymous
    • 5 years ago
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    Mine should be \[15[5x^2(x−2)−(x−2)]\] \[=15(5x^2-1)(x-2)\]

  19. anonymous
    • 5 years ago
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    gotcha

  20. anonymous
    • 5 years ago
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    alright i will be back in a few with some more

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