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anonymous
 5 years ago
f(x)=(3x^4)*sqrt(x) + 7/x^2*(sqrt(x))
f '(x)= ??
anonymous
 5 years ago
f(x)=(3x^4)*sqrt(x) + 7/x^2*(sqrt(x)) f '(x)= ??

This Question is Closed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0change the square root to an exponent

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.03x^4 x^(1/2) + 7/(x^2 x^(1/2))

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.03x^(9/2) + 7/(x^5/2) and work that....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0do you know how to do a derivative?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.07/(x^5/2) is its own term right? or is that (x^(5/2)) the demoniator of the whole equation?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0d..e...n..o..m...i..n...a..t...o....r.. lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0o shoot , i thought i was replying to you but it wasnt posting

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, i know how to find derivatives

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just dont know where i am going wrong

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0step me thru what you have done and I will let you know :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(i had made them exponents as well)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the first term is a breeze.... just multiply exponent and subtract "1" from it.....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.03x^(9/2) = 3(9/2)x^(7/2) = 27 x^(7/2)  2 right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry got kicked out, yes that is what i have

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x^(7/2) = x^(6/2) x^(1/2) so if you want to clean it up some: 17 x^3 sqrt(x)  for the first term... 2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.07  how would you derive this term? (x^(5/2))

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oo i had x^3/2 not x^5/2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0quotient rule: I remember it like this: BT'B'T  where B=bottom, and T=top B^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0whose right then, me or you :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when you are combining x^2 and x^1/2 dont you add the exponents?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yes... 2 + 1/2 = a mixed numeral...tern it into an improper fraction 2(2)+1 5  =  2 2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol...a tern is a sea bird i think

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.07  lets derive this... (x^(5/2))

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0may i ask you one more derivative question?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.05 x^(3/2) B' =  and T' = 0 2 35 x^(3/2)  2  x^5 Is what I get...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sure, but lets finish this one first :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i plugged it in my school system and got the right answer :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0they dont tell you what the answer is, just if you get it correct ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if f(x) = sqrt(6x) f 'x = ?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02 ways to do this; we can do a substituion and the chain rule? or simply change to exponent and solve it.. which way you want it?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ok.... sqrt(6x) = (6x)^(1/2) ....might have to still do the "extra" because of that (6x) in there...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is this correct 1/(2(6x)^1/2)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(1/2)(6x)^(1/2) cleans up to: 1  ;we got to multiply (use the chain rule) to use that "6x" 2sqrt(6x)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that didnt turn out the way I wanted lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.01  times Dx(6x) 2sqrt(6x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont understand why you are taking the derivative of 6x

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.06/2 = 3 3  sqrt(6x)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0let me explain it like this: remember when we have f(g(x)) and want to derive it?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0we have to use the "chain rule" to solve it right? this problem is exactly that set up, let me show you..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry, keep getting kicked out. i havent learned the chain rule

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y = sqrt(u) and u = 6x to solve dy/dx we need the chain rule: (dy/dx) = (dy/du) (du/dx) y = sqrt(u) dy/du = 1/2sqrt(u) u = 6x du/dx = 6 Do you see it?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Do you understand it? Imagine a set of gears that are meshed together, when the first one is turned, all the others turn as well. But they depend on the funtion of the first one to determine how they are going to behave.... does that makes sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now i understand how you got to your final answer. thank you so much for all of your help!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0definitely a 'fan' of you :)
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