A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

solve for x and y |x y| minus |-y x| |-y x| |x y | equals |4 6| |-4 6| This is a matrix problem and i dont understand it.

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    see http://en.wikipedia.org/wiki/Matrix_addition

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So im supposed to subtract the x's and y's?

  3. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Generally, \[ \left[ \begin{array}{cc} a & b \\ c & d \end{array} \right] + \left[ \begin{array}{cc} e & f \\ g & h \end{array} \right] = \left[ \begin{array}{cc} a+e & b+f \\ c+g & d+h \end{array} \right] \] In this case, \[ \left[ \begin{array}{cc} x & y \\ -y & x \end{array} \right] - \left[ \begin{array}{cc} -y & x \\ x & y \end{array} \right] = \left[ \begin{array}{cc} x & y \\ -y & x \end{array} \right] + \left[ \begin{array}{cc} y & -x \\ -x & -y \end{array} \right] \] \[= \left[ \begin{array}{cc} x+y & y-x \\ -y-x & x-y \end{array} \right] = \left[ \begin{array}{cc} 4 & 6 \\ -4 & 6 \end{array} \right] \] Now you effectively have 4 equations in two variables, so you should be able to either solve for each variable or show that no solutions satisfy all four equations.

  4. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I solved this and got x=-1 and y=5. is that correct?

  5. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ... \[ \left[ \begin{array}{cc} x+y & y-x \\ -y-x & x-y \end{array} \right] = \left[ \begin{array}{cc} -1+5 & 5+1 \\ -5+1 & -1-5 \end{array} \right] = \left[ \begin{array}{cc} 4 & 6 \\ -4 & -6 \end{array} \right] \] no, that doesn't look right. \[y-x=6 \rightarrow y=x+6; \ \ \ x-y=6 \rightarrow y=x-6; \ \ \ 6 \neq -6\] I don't think there is a solution.

  6. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I cant see the third matrix

  7. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    where the 4s are

  8. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.