2log(base8)4-(1/3)log(base8)8=x

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2log(base8)4-(1/3)log(base8)8=x

Mathematics
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What number are both 8 and 4 a power of?
log(base8)4^2-log(base8)8^(1/3)=log(base8)[4^2/8^(1/3)]
Are you good now smurfy?

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Other answers:

sorry for late response i didnt see my new notifications! um i get what myininaya did but what would you do after that?
simplify!
=log(base8)[16/2] i will let you do the last step
or last two steps
so x=1 correct?
:) YES!
whoo thanks so much!
think you could help me with one more?
ok
2. Jamal has a game with 2 groups of tiles. The first group of 26 tiles is labeled with all the letter of the alphabet, The second group of 10 tiles is #0-9. If Jamal draws one letter tile and one # tile at the random, what is the probability that he will draw a letter in his name and an odd number? A. (1/13) B. (5/52) C. (1/4) D. (7/26)
i got 17/26 :(
let me think about it
ok and ya all the answers tht i was getting werent on there either :P
i suck at probability, but give me a few and I will think
I get A
could u plz explain it to me?
did you P(AUB)=P(A)+P(B)-P(A and B)
No, I used the probability of two independent events is their product.
So how many ways can Jamal draw a letter that is in his name?
jaml
its independent events because A has nothing to do with B good thinking bond
right, so 4/26
someone explain how rhey got A!
dont worry about A
Now, how about the probability of pulling an odd tile?
1/10
how many odd numbers are between 0 and 9?
ohhhh ODD 5/10!
ok so since they are independent events you multiply the (5/10)(4/26)
ok see ididnt get it bc ithought it said 1/10 not 5/10 imissedthe odd part lol thanks!!
lol
one more q! 3^2x=7^(x-1)
Eeek, that doesn't look good...
hahaha
q! is read as q factorial?
jk lol i know you mean another question!
take the natural log of both sides
you mean get the decimal form of both? if so thats what i did but for some reason i came out with a negative # :(
ln3^(2x)=ln7^(x-1)
2xln3=(x-1)ln7
2xln3=xln7-ln7
2xln3-xln7=-ln7
x(2ln3-ln7)=-ln7
x=-ln7/(2ln3-ln7)
x=-ln7/(ln8-ln7)
x=-ln7/(ln(8/7))
ok i see so b4 i write the work does the answer comeout positive?
you have a negative in front of it so its negative
ok so were allowed to have a negative as the answer?
ln(negative)=does not exist ln(0) does not exist -lna exist if a>0
so the answer is?
the answer to?
are we still talking about the previous solution?
ya the one with the negative
so you are saying its not a solution? why do you say that?
what? i just want to know what you got for the answer lol
we can check it to see
youre confusing me
you want to know if it is a solution. if you ever have doubt about something, check it
no i dont want to know if it is a solution i just want to know the answer lol so would the answer be "no solution"?
give me just sec and i will check k??
it is a solution if i did each step correctly
so the final answer is....?
you know like x=?
i can scroll back up and look just sec
it says x=-ln(7)/(ln(8/7))
so if you put that in your calc what is the number? (sorry i dont have a good calc with me)
> evalf(solve(3^(2*x) = 7^(x-1))); -7.742930467 >
ok thanks!
smurfy it is not easy to check the solution, but it is the solution because exponential functions are continuous everywhere
but logarithmic functions are not continuous everywhere log(baseb)x=lnx/lnb so whenever the base is 1 or negative or 0 and whenever x is negative or 0, the the function is undefined

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