A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
when do you use the inverse when doing logs?
anonymous
 5 years ago
when do you use the inverse when doing logs?

This Question is Closed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0log is the inverse of exponents; and exponents are the inverse of logs. What is your question regarding?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont understand how to do them at all. how would you graph y=3log(base5)x. how would you go about that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hey amistre can you please help me with 2 antiderivative questions after you are done here?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Since y = 3 log5(x) is the same as: y = log5(x^3) we can more easily graph its inverse and then "flip" the graph about the y=x line.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you got a question posted we can go to :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you get the second equation from switching the x and ys and solving for y?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you see my question

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, but I messed it up in my head the first time :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0meet me there when you can help me

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0mini: log graphs can be hard to do without a calulator; so we can rewrite it to a more familiar form... do you agree?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but how do you make it in the other form?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y = 3 log5(x) ; divide by 3 y/3 = log5(x) ; take the 5^ of each side 5^(y/3) = 5^(log5(x)) ; 5^(log5) cancel each other out. 5^(y/3) = x Do you agree? Are you familiar with the rules for logs?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i understand how you did that. when is that that you go about switching the x and y to solve?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0When it makes the graphing easier you can modify it. All you are doing is solving for x instead of y, so keep aware of that

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Would you agree that 5^(y/3) is easier to plot for and solve than log5(x) ? :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do you do for example logbase8 4096=4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Do you mean: log8(4096) = 4 ??

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that is what is known as an identity. one side equals the other. Lets take for example: logB(x) = y this means that B^y=x We can take your equation for instance: log8(4096) = 4 means: 8^4 = 4096, we can test that by either pen and paper , or calculator :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.035^log35 = 1 and we are left with "x"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you do the inverse of y=log1/4 x out step by step please?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0is that log base (1/4)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i understand that one now but how do you do the second one?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just y= ln 6x not base 6x

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0"ln" is just a special way they write log to the base "e"

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y = ln(6x) e^y = e^ln(6x) e^y = 6x (e^y)/6 = x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how about y= ln (x+2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so for the graph of y=log8 x2 you would do 8^y=x2 and then fill in values for y such as 0 which would be 1=x2 x=3?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.