the function f is defined for all real numbers x by f(x) = ax^2 + bx + c where a, b and c are constants and a is negative, in the xy-plane, the x coordinate of the vertex of the parabola is y=f(x) is -1. if t is a number for which f(t) > f(0), which of the following (any or all) must be true?
1: -2 < t < 0
2: f(t) < f(-2)
3: f(t) > f(1)
please help!

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we know this parabola is oven downward because a is negative and the vertex is (-1,k)

f(t)>f(0) ....

f(t)=a(t+1)^2+k and f(0)=a(0+1)^2+k=a+k and f(t)>f(0) so we have a(t+1)^2+k=a+k

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