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anonymous
 5 years ago
In solving the system 4x + 6y = 1 and x + 1.5y = 0, Sue arrived at the equation 0 = 1 . Assuming Sue did not make a mistake, that means the system has:
a. (0, 1) as its only solution
b. infinitely many solutions
c. no solution
d. (1, 0) as its only solution
e. has (0, 1) and (1, 0) as its only solutions
anonymous
 5 years ago
In solving the system 4x + 6y = 1 and x + 1.5y = 0, Sue arrived at the equation 0 = 1 . Assuming Sue did not make a mistake, that means the system has: a. (0, 1) as its only solution b. infinitely many solutions c. no solution d. (1, 0) as its only solution e. has (0, 1) and (1, 0) as its only solutions

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.00 = 1?? That doesn't make any sense.. right? so (C) no solution
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