anonymous 5 years ago How do I get the x and y intercept of 4-2^x+3?

1. anonymous

The x intercept occurs when y = 0. And the y intercept occurs when x = 0. Since your equation is y = 4 - 2^x +3, simply plug in 0 for one of the two variables, and solve for the other.

2. anonymous

How would I go on solving for x? That's what confuses me. I understand how to get the y.

3. anonymous

0=4-2^x 2^x=4 x = 2 (since 2² = 4)

4. anonymous

Is the equation: $y=4-2^x + 3$ or $y=4-2^{x + 3}$

5. anonymous

oops sorry forgot about the 3

6. anonymous

i need to sleep lol ... sorry

7. anonymous

To get a variable out of the exponent one would typically use a log function. Unless you can do it easily by inspection.

8. anonymous

The second one Polpax. Thanks for trying kiwi :)

9. anonymous

Ok, so $y=0 \rightarrow 2^{x+3} = 4$ Since we know $4 = 2^2 \rightarrow 2^{x+3} = 2^{2} \rightarrow x+3 = 2 \rightarrow x = ?$

10. anonymous

Thanks Polpak :)