anonymous
  • anonymous
How do I get the x and y intercept of 4-2^x+3?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
The x intercept occurs when y = 0. And the y intercept occurs when x = 0. Since your equation is y = 4 - 2^x +3, simply plug in 0 for one of the two variables, and solve for the other.
anonymous
  • anonymous
How would I go on solving for x? That's what confuses me. I understand how to get the y.
anonymous
  • anonymous
0=4-2^x 2^x=4 x = 2 (since 2² = 4)

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anonymous
  • anonymous
Is the equation: \[y=4-2^x + 3\] or \[y=4-2^{x + 3}\]
anonymous
  • anonymous
oops sorry forgot about the 3
anonymous
  • anonymous
i need to sleep lol ... sorry
anonymous
  • anonymous
To get a variable out of the exponent one would typically use a log function. Unless you can do it easily by inspection.
anonymous
  • anonymous
The second one Polpax. Thanks for trying kiwi :)
anonymous
  • anonymous
Ok, so \[y=0 \rightarrow 2^{x+3} = 4\] Since we know \[4 = 2^2 \rightarrow 2^{x+3} = 2^{2} \rightarrow x+3 = 2 \rightarrow x = ?\]
anonymous
  • anonymous
Thanks Polpak :)

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