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anonymous

  • 5 years ago

How do I get the x and y intercept of 4-2^x+3?

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  1. anonymous
    • 5 years ago
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    The x intercept occurs when y = 0. And the y intercept occurs when x = 0. Since your equation is y = 4 - 2^x +3, simply plug in 0 for one of the two variables, and solve for the other.

  2. anonymous
    • 5 years ago
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    How would I go on solving for x? That's what confuses me. I understand how to get the y.

  3. anonymous
    • 5 years ago
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    0=4-2^x 2^x=4 x = 2 (since 2² = 4)

  4. anonymous
    • 5 years ago
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    Is the equation: \[y=4-2^x + 3\] or \[y=4-2^{x + 3}\]

  5. anonymous
    • 5 years ago
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    oops sorry forgot about the 3

  6. anonymous
    • 5 years ago
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    i need to sleep lol ... sorry

  7. anonymous
    • 5 years ago
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    To get a variable out of the exponent one would typically use a log function. Unless you can do it easily by inspection.

  8. anonymous
    • 5 years ago
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    The second one Polpax. Thanks for trying kiwi :)

  9. anonymous
    • 5 years ago
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    Ok, so \[y=0 \rightarrow 2^{x+3} = 4\] Since we know \[4 = 2^2 \rightarrow 2^{x+3} = 2^{2} \rightarrow x+3 = 2 \rightarrow x = ?\]

  10. anonymous
    • 5 years ago
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    Thanks Polpak :)

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