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anonymous
 5 years ago
X^2+2y=9
xy+3=0
could someone show me the steps to solving this?
anonymous
 5 years ago
X^2+2y=9 xy+3=0 could someone show me the steps to solving this?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you are finding x and y then : 1) call the first equation(a) and second equation(b) 2) solve for y in equation(b) and you'll get: \[y = x + 3\] then substitute y in equation(a) and you'll get : \[x^2 + 2(x + 3)  9 = 0 \] \[x^2 + 2x 3 = 0\]\[(x1)(x+3) = 0\] then you have : x = 1 and x = 3 Substitute both x's in equation (b) to find y, so for the first x = 1, you'll get : y = 1 + 3 y = 4 and for the second x = 3, you'll get : y = 3 + 3 y = 0 In summary, your 2 points are : (1,4) and (3,0) ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you understand how to solve such problems now? :)
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