X^2+2y=9 x-y+3=0 could someone show me the steps to solving this?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

X^2+2y=9 x-y+3=0 could someone show me the steps to solving this?

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

If you are finding x and y then : 1) call the first equation(a) and second equation(b) 2) solve for y in equation(b) and you'll get: \[y = x + 3\] then substitute y in equation(a) and you'll get : \[x^2 + 2(x + 3) - 9 = 0 \] \[x^2 + 2x -3 = 0\]\[(x-1)(x+3) = 0\] then you have : x = 1 and x = -3 Substitute both x's in equation (b) to find y, so for the first x = 1, you'll get : y = 1 + 3 y = 4 and for the second x = -3, you'll get : y = -3 + 3 y = 0 In summary, your 2 points are : (1,4) and (-3,0) ^_^
do you understand how to solve such problems now? :)
absolutly! thanks!

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Not the answer you are looking for?

Search for more explanations.

Ask your own question