## anonymous 5 years ago 4^-2+2*3^-2

1. anonymous

$4^{-2}+2\times3^{-2}=\frac{1}{4^2}+2 \times \frac{1}{3^3}=\frac{1}{16}+\frac{2}{9}=\frac{9+16 \times2}{16 \times 9}=\frac{41}{144}$

2. anonymous

$=\frac{41}{144}$in case the site cut the answer off above. Just remember what the minus sign on the exponent does - $a^{-n}=\frac{1}{a^n}$