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anonymous

  • 5 years ago

lim (x^2) / (cos4x - cos9x) as x->0

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  1. anonymous
    • 5 years ago
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    what happens when you plug zero into the equation?

  2. anonymous
    • 5 years ago
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    Indeterminate form. 0/0

  3. anonymous
    • 5 years ago
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    right, so what can we do from here?

  4. anonymous
    • 5 years ago
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    L'Hospital Rule.

  5. anonymous
    • 5 years ago
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    right, and what do we get from that?

  6. anonymous
    • 5 years ago
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    Nvm. L'Hospital wont work in this situation.

  7. anonymous
    • 5 years ago
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    why not?

  8. anonymous
    • 5 years ago
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    It is still indeterminate. sin(0)=0

  9. anonymous
    • 5 years ago
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    right, so we can do L'Hopitals rule again

  10. anonymous
    • 5 years ago
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    True. I forgot about it.

  11. anonymous
    • 5 years ago
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    after the second derivative you are left with 2 in the numerator, and cosines in the denominator, so you should be good from there

  12. anonymous
    • 5 years ago
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    when you do L'Hopitals rule again rather

  13. anonymous
    • 5 years ago
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    Do you have an answer?

  14. anonymous
    • 5 years ago
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    yes 0.0307692

  15. anonymous
    • 5 years ago
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    yes, 0.030769

  16. anonymous
    • 5 years ago
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    also 2/65

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spraguer (Moderator)
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