A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • 5 years ago

find the area of a regular hexagon with side 2 sqrt 3 cm and apothem 3 cm.

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The apothem of a regular polygon is a line segment from the center to the midpoint of one of its sides. If you break the hexagon into six congruent triangles, each triangle will have a base of 2sqrt(3) and apothem, which is the perpendicular height, 3. The area of a triangle is \[1/2 \times (base) \times (perpendicular.height)\]which is \[\frac{1}{2} \times 2 \sqrt{3} \times 3= 3 \sqrt{3}\]But you have six of these triangles, so your area is then\[6 \times 3 \sqrt{3} = 18 \sqrt{3}\]

    1 Attachment
  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.