anonymous
  • anonymous
(3x)/(x+1)=12/(x^2-1)+(x+4)/(x-1)
Mathematics
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anonymous
  • anonymous
(3x)/(x+1)=12/(x^2-1)+(x+4)/(x-1)
Mathematics
katieb
  • katieb
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
Let's write it down first:\[= (3x/x+1) - (12/(x+1)(x-1)) - (x+4/x-1)\] multiply by x + 1 and x-1 to get the same denominator and you'll get : \[= [3x(x-1)/(x+1)] - [12/(x-1)(x+1)] + [(x+4)(x+1)/(x-1)(x+1)] \] \[= (3x^2 - 3x -12 - x^2 - 5x - 4)/(x-1)(x+1)\] \[= (2x^2 - 8x -16)/(x+1)(x-1)\]
anonymous
  • anonymous
from the 2nd line it's [(x+14)(x+1)/(x+1)(x-1)] sorry ^^" hope it's clear now ^_^
radar
  • radar
Were you to solve for x. There is an equal sign in that equation. As you can see it works down to a quadratic equation divided by another second degree equation

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