## anonymous 5 years ago compute the integral: (8x^2+6)/(x^2+1)(x+7)

1. anonymous

It is basically $\int\limits_{}^{} 8x ^{2}+6 - \int\limits_{}^{}x ^{3}+7x ^{2}+x+7$

2. anonymous

thank you so much

3. anonymous

i also have another question :( compute the indefinite integral: dx/(x^2+4)^(5/2)

4. anonymous

i am sorry, I was thinking of logarithms. Please ignore my previous answer. My integration is rusty. i'll get back to you with the correct answer.

5. anonymous

okay

6. anonymous

the original question is; compute the integral:$\int\limits_0{}^{1} (8x^2+6) / (x^2+1)(x+7) dx$

7. anonymous

do you know integration by partial fractions? Understanding of that is essential to this problem http://www.math.ucdavis.edu/~kouba/CalcTwoDIRECTORY/partialfracdirectory/PartialFrac.html scroll down till you see how the partial fractions are done

8. anonymous

thanks !

9. anonymous

This is how to solve your problem. The numerator in this example is also a quadratic equation and the denominator is a cubic equation: http://www.math.ucdavis.edu/~kouba/CalcTwoDIRECTORY/partialfracsoldirectory/PartialFracSol2.html#SOLUTION%209

10. anonymous

got it:)

11. anonymous
12. anonymous

http://openstudy.com/updates/4d948f880ffe8b0bcdc9a720 can you help me with that problem ? :(

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