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anonymous
 5 years ago
compute the integral: (8x^2+6)/(x^2+1)(x+7)
anonymous
 5 years ago
compute the integral: (8x^2+6)/(x^2+1)(x+7)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It is basically \[\int\limits_{}^{} 8x ^{2}+6  \int\limits_{}^{}x ^{3}+7x ^{2}+x+7\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i also have another question :( compute the indefinite integral: dx/(x^2+4)^(5/2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am sorry, I was thinking of logarithms. Please ignore my previous answer. My integration is rusty. i'll get back to you with the correct answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the original question is; compute the integral:\[\int\limits_0{}^{1} (8x^2+6) / (x^2+1)(x+7) dx \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you know integration by partial fractions? Understanding of that is essential to this problem http://www.math.ucdavis.edu/~kouba/CalcTwoDIRECTORY/partialfracdirectory/PartialFrac.html scroll down till you see how the partial fractions are done

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is how to solve your problem. The numerator in this example is also a quadratic equation and the denominator is a cubic equation: http://www.math.ucdavis.edu/~kouba/CalcTwoDIRECTORY/partialfracsoldirectory/PartialFracSol2.html#SOLUTION%209

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.math.ucdavis.edu/~kouba/CalcTwoDIRECTORY/partialfracsoldirectory/PartialFracSol.html#SOLUTION%206 this too might help!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://openstudy.com/updates/4d948f880ffe8b0bcdc9a720 can you help me with that problem ? :(
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