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anonymous
 5 years ago
how do i put ln[ sectheta + tantheta] in terms of x
anonymous
 5 years ago
how do i put ln[ sectheta + tantheta] in terms of x

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a. There's no "x" in this expression. b. In order to put it in terms of a variable; it has to be in an equation form.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the ogrinal equation from solving it was intergal of dx/1x^2 if that helps

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0true, isn't there a given x np?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0HaHaHA (breaking down due to extreme lough)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, what's so funny angoo?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ahhh, so you used a trig substitution. Now, go back to whatever value you used for x to solve the integral (in terms of theta), solve for sec(theta) and tan(theta) by drawing out the triangles, and put those values  in terms of x  in your final expression.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just wrote that to make you smile

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you understand what Quantum said np65? ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and it made me smile :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so i have the triangle would that put me at 1x^2+x then?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what was your value of x when you integrated?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What trig substitution for x did you use to solve the integral?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you set x = sin?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alright i have the intergal of dx1x^2 i set u =sintheta and du = costheta dtheta i then subed in u and du

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0following that i got dtheta/costheta

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh I got it!\[x = \sin \theta\] and you know that sin x = opposite/hyp your opposite in this case = x hyp = 1 draw the triangle and you'll be able to continue from here ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hence :\[\sec \theta= 1/\cos \theta\] \[\tan \theta = \sin \theta/ \cos \theta\] you have sin (theta), now find cos (theta) :) is it clear now?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so then the other side would be 1x^2 or use the pthag therom to get the last side making it the sqrroot(x^2+1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use the pyth.theorem :) that's it. you just don't have x, find it by applying the theorem , then find cos (theta)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the last side will be : \[\sqrt{1 x^2}\] ^_^
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