anonymous
  • anonymous
how do i find the critical numbers for cube root of X+2 . I took the derivative of this and got (1)/[3(x+2)^(-2/3)]. is the next step setting this expression equal to 0?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
yes
anonymous
  • anonymous
but Im having problem solving for 0 at this point.
anonymous
  • anonymous
one sec

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anonymous
  • anonymous
and consider the x that will make the equation undefined as a critical number
anonymous
  • anonymous
make the derivative i mean
anonymous
  • anonymous
so I have to substitute a value for x that will make this expression ---> (1)/[3(x+2)^(-2/3)]. equal 0?
anonymous
  • anonymous
your derivative should be 3x^2+12x+12
anonymous
  • anonymous
if I substitute -2 for x, the entire denominator equals 0. so would -2 b my critical number?
anonymous
  • anonymous
yes you cant find a number that can make your derivative equal to 0 so -2 is the only critical number
anonymous
  • anonymous
ohh okay!!! thanks a lot! :)
anonymous
  • anonymous
@pineda isnt the derivative wrong?
anonymous
  • anonymous
I think its right. I double checked it on my calculator
anonymous
  • anonymous
it looks fine for me its \[1/3\sqrt[3]{x+2^{2}}\]
anonymous
  • anonymous
is the equation \[(x+2)^{3}\]
anonymous
  • anonymous
pineda100 is right
anonymous
  • anonymous
its \[\sqrt[3]{x+2}\]
anonymous
  • anonymous
yeah
anonymous
  • anonymous
oh oops read it wrong
anonymous
  • anonymous
^_^
anonymous
  • anonymous
original equation is \[\sqrt[3]{ }x+2\]. sorry i coudlnt get the square root sign to appear completely
anonymous
  • anonymous
ya then pineda is correct. my bad.
anonymous
  • anonymous
okay thanks a lot for your help pineda and everyone else who contritbuted! much appreciated! :)

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