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find your \[\mu\]
e is going to be raised by this
can you please solve it step by step because im really bad at math
in the end you are just going to end up with x, so multiply both sides of the equation by this
e^lnx= just x
x(dy/dx)+y is just (xy)(dy/dx)
from here you can separate and put your y's with dy and x's with dx
this will give you (dy/y^2)=dx, just integrate now
god bless you.. but i really suck at math and i have two exams tomorrow so i cant study for them both
i truly appreciate your help, but if any one of you guys could do the whole thing, you would save my life
This is a bernoulli's equation. You have to make the substitution v=y^(-2). v' will then equal=-2y^(-3)dy/dx. Sub in dy/dx from the original equation. Things will cancel only leaving you with v and x. Solve this new equation as a linear 1st order and then sub back in your v's with y's.
the final answer should be y=1/-(x+c)
or play with the constants and you should get y=1/(x+c)
I don't think that's the solution mathtio, I'm not quite sure what you're doing
can you please solve the problem step by step because im so tired and i still have so much to study I HONESTLY APPRECIATE YOUR HELP SO MUCH GUYS :) thank you
mathtio is tryign to solve this as a linear first order, but you can't because the right side is in terms of y and not x
you are right. I forgot about the exponent in the y.
attention to detail.....spaceknight should be able to help you better than i can.
sorry for the confusion.
its ok thank you for trying.. its much appreciated
this thing is not linear
can you help me?
instead of waiting for every step you can at least try doing it, the problem is pretty straight forward once you get started on it
yes but my problem is that i dont get it at all.. I have always had problem with math.. i wish i could understand math half as well as you can.. if i knew how to solve it i wouldnt be asking for help :S
@spaceknight, am afraid you cannot get rid of y even if you sub with v.
Yes you can. The y's can all be substituted nicely with v's. And, what part of my solution don't you understand? You can't just look at a problem and say you don't get it. If you don't even understand the very basics on how to start, even if I posted step by step solutions you wouldn't get it
i just need a solution, thats all.
If you want the solution, you can use wolframalpha y^2=-1/(-Cx^2-2x)
thanks i guess