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anonymous

  • 5 years ago

find the general solution of the following differential equation: y'-2x=x

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  1. anonymous
    • 5 years ago
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    It's separable. Move the 2x over to get dy/dx=3x. Multiple both sides by dx to get dy=3xdx. Integrate both sides.

  2. anonymous
    • 5 years ago
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  3. anonymous
    • 5 years ago
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    Well, I figure something was wrong because the original problem was kinda dumb lol. Anyways, it's already in linear first order form. So you need to find the integrating factor which is e^integral of (p(x)). p(x) happens to be -2x. So you will get e^(x^2). Multiple both sides by the integrating factor. The left side simplies into ye^(-x^2)

  4. anonymous
    • 5 years ago
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    Well, I figure something was wrong because the original problem was kinda dumb lol. Anyways, it's already in linear first order form. So you need to find the integrating factor which is e^integral of (p(x)). p(x) happens to be -2x. So you will get e^(x^2). Multiple both sides by the integrating factor. The left side simplies into ye^(-x^2)' and the right side becomes xe^(x^2). Integrate both sides and you have your solution. Sorry posted last one before I was done.

  5. anonymous
    • 5 years ago
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    thnx a lot

  6. anonymous
    • 5 years ago
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    hej spaceknight im sorry but i have another question,i have exam tomorrow and i find this test,beacuse i dont have time to study,can u solve these problems step by step pls and send me back the answers

  7. anonymous
    • 5 years ago
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    No i dont have time to do them all in full lol, i can tell you how to solve each one like I did above though if you want

  8. anonymous
    • 5 years ago
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    Also, if you don't have time to study and just want to look at solutions lol good luck that will not work well in differential equations

  9. anonymous
    • 5 years ago
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    no i can't solve like this,but thnx for u're help :D

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