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anonymous

  • 5 years ago

A 10 ohm resistor is connected across a 120V rms sinusoidal 60Hz line. what value is the closest to the average current flowing in the resistor between t=0 and t=.0042 sec? (Hint V=120√(2)sin120pi t)

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  1. radar
    • 5 years ago
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    Convert the 120 RMS to Average, divide by the 10 Ohm resistor.

  2. anonymous
    • 5 years ago
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    Thank you!!!!!

  3. anonymous
    • 5 years ago
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    radar can you help me ?

  4. radar
    • 5 years ago
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    There is a conversion factor, but I do it the hard way first I convert RMS to Peakk, then peak to Average 120 x 1.414 = 170 peak, then multiply 170 x .6366 = 108 avg volts. The rest is history.

  5. radar
    • 5 years ago
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    Oh Oh looking up at your original you are asking for the instantaneous avg current at two specific times. I was just computing the overall average current for 1/2 cycle. You are making the problem difficult or at least someone Is. Note the multiplying of 120 by the sqrt of 2 This is the conversion to pk voltage.

  6. radar
    • 5 years ago
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    I am going to have to do some review! I will get back to you.

  7. anonymous
    • 5 years ago
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    Hey Radar,Thank you for your replays.I get it after your first replay.Some nick name Emy mistakenly did ask you for help on my page.

  8. radar
    • 5 years ago
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    O.K. alma1969. But I am stumped for the time being.

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