A 10 ohm resistor is connected across a 120V rms sinusoidal 60Hz line. what value is the closest to the average current flowing in the resistor between t=0 and t=.0042 sec? (Hint V=120√(2)sin120pi t)
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Convert the 120 RMS to Average, divide by the 10 Ohm resistor.
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There is a conversion factor, but I do it the hard way first I convert RMS to Peakk, then peak to Average 120 x 1.414 = 170 peak, then multiply 170 x .6366 = 108 avg volts. The rest is history.
Oh Oh looking up at your original you are asking for the instantaneous avg current at two specific times. I was just computing the overall average current for 1/2 cycle. You are making the problem difficult or at least someone Is.
Note the multiplying of 120 by the sqrt of 2 This is the conversion to pk voltage.
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