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anonymous
 5 years ago
how would u solve:
sq rt of 24rs times sq rt of 6r^3s^4 times sq rt of rs^2
anonymous
 5 years ago
how would u solve: sq rt of 24rs times sq rt of 6r^3s^4 times sq rt of rs^2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt[2]{24rs}\times \sqrt[2]{6r^3s^4}\times \sqrt[2]{rs^2}\]

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Sqrt(24rs x 6r^3s^4 x rs^2)

radar
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{144 xr ^{5}s ^{7}}\]

radar
 5 years ago
Best ResponseYou've already chosen the best response.0\[12r ^{2}s ^{3}\sqrt{rs}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but how did u get that?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0The first equartion placed all the terms in one radical becoming factors producing the second line.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0The third line shows taking the perfect squares and placving their roots outside the radical.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0leaving only the factors which were not perfect squares in the radical. Note you can start from the finish and work backwards and come up with your original expression. The 12 goes back as 144 the r^2 goes back as r^4 ......etc.
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