anonymous
  • anonymous
choose x to max log(1-x)
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
k so u cant take log of a negative number .... its a property will be helpful to memorize it .... max x = 1
anonymous
  • anonymous
right..how would i solve with first order conditions?
anonymous
  • anonymous
it has no maximum value.. it goes to infinity as x goes to negative infinity

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anonymous
  • anonymous
can you solve this with derivatives?
anonymous
  • anonymous
yeah the derivative of log(1-x)=-1/(1-x) when you set it equal to zero, it has no solution.. therefore, there are no extreme values to the given function
anonymous
  • anonymous
i see that makes sense, however in a similar problem the answer says x = 0, i.e., choose x to maximize (y - x)
anonymous
  • anonymous
sorry the question is choose x to maximize log(y-x)
anonymous
  • anonymous
are you sure about the answer? that it's x=0
anonymous
  • anonymous
because I think negative values of x give greater values for the function log(y-x) than x=0
anonymous
  • anonymous
oh i think they are assuming that x greater than or equal to zero
anonymous
  • anonymous
I see
anonymous
  • anonymous
then i'm not sure how the derivate would yield x=0
anonymous
  • anonymous
any ideas?

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