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anonymous
 5 years ago
For finding the area bounded by y=sinx, y=x, and x=pi/4 i took the integral of (xsinx)dx from 0 to pi/4 got x^2/2+cosx but im not getting the right answer when i plug in pi/4. (the right answer should be 0.0155 units^2) is there an error in my integration that still evades me or is it a bigger error?
anonymous
 5 years ago
For finding the area bounded by y=sinx, y=x, and x=pi/4 i took the integral of (xsinx)dx from 0 to pi/4 got x^2/2+cosx but im not getting the right answer when i plug in pi/4. (the right answer should be 0.0155 units^2) is there an error in my integration that still evades me or is it a bigger error?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you made a mistake when you wrote x  sin(x) dx. DRAW THE GRAPH FIRST! when you do these kind of questions. I cannot believe how many times I have messed these types of questions up on the test. DRAW THE DAMN THING! even if you draw it roughly you will get the correct answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I graphed it on my calculator. so (sinxx)dx?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you sure your answer is right? try this ... x^2/2 + cos(x) > (0 + cos(0))  (pi^2/32) + cos(pi/4) 1  (pi^2/32)  1/sqrt(2) = right answer?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nono x  sin(x) is correct.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry take the negative of my answer 1 + (pi^2/32) + 1/sqrt(2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that should be right. if it not right then the multiple choice you are given has no correct answers
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