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anonymous

  • 5 years ago

A truck has a minimum speed of 15 mph in high gear. When traveling x mph, the truck burns diesel fuel at the rate of 0.0110469 ( 1156/x + x) gal/mile. Assuming that the truck can not be driven over 54 mph and that diesel fuel costs $1.21 a gallon, find the steady speed that will minimize the total cost of the trip if the driver is paid $20 an hour.

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  1. anonymous
    • 5 years ago
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    \[\delta y/\delta x (0.0110459 (1156/x+x)=0\] the derivative is \[0.01101459(-1156/x^2+1)\] then you just solve for x, which it would be 34 mpg

  2. anonymous
    • 5 years ago
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    that was the answer of another part of this question, which is : The steady speed that will minimize the cost of the fuel for a 620 mile trip

  3. anonymous
    • 5 years ago
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    oh srry, didnt see the other one

  4. anonymous
    • 5 years ago
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    that should be the right answer though, because it consumes the least about of gasoline

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