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anonymous
 5 years ago
How to find the maximum, the minimum and the xintercepts in the interval (2pi, 2pi)? The equation is y=3 cos x/2
anonymous
 5 years ago
How to find the maximum, the minimum and the xintercepts in the interval (2pi, 2pi)? The equation is y=3 cos x/2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have not received any help yet. I would really appreciated it because I am struggling with finding how to solve this problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the xintercepts occur when y=0. so u set the equation to equal zero then solve for x. so x=2*arcos (0). then u differentiate the equation to get dy/dx = 3/2sin(x/2). then set this to equal zero and solve for x. then put your ans into the original function to solve for y. this gives u ur max and min value
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