Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
j30lex10
Group Title
Hooke's Law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. If the distance is 23 cm when the weight is 3 kg, what is the distance when the weight is 5 kg? I need the answer badly and I do not understand the problem.
 3 years ago
 3 years ago
j30lex10 Group Title
Hooke's Law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. If the distance is 23 cm when the weight is 3 kg, what is the distance when the weight is 5 kg? I need the answer badly and I do not understand the problem.
 3 years ago
 3 years ago

This Question is Closed

ashwinram Group TitleBest ResponseYou've already chosen the best response.0
distance d is directly proportional to weight w so, d = k * w (where k is some constant you don't know yet)
 3 years ago

ashwinram Group TitleBest ResponseYou've already chosen the best response.0
when d = 23, w = 3 so, 23 = k * 3 which means k = 23/3
 3 years ago

ashwinram Group TitleBest ResponseYou've already chosen the best response.0
now, you have to find d when w = 5 d = k * w = 23/3 * 5
 3 years ago

ashwinram Group TitleBest ResponseYou've already chosen the best response.0
another way of thinking about it: 3 kg stretches the spring by 23 cm so 5 kg will stretch it even more
 3 years ago

ashwinram Group TitleBest ResponseYou've already chosen the best response.0
3 kg stretches it by 23 cm in other words, each kg stretches it by 23/3 cm so, 5 kg will stretch it 5 times that much = 5 * 23/3
 3 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.