Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Hooke's Law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. If the distance is 23 cm when the weight is 3 kg, what is the distance when the weight is 5 kg? I need the answer badly and I do not understand the problem.

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer


To see the expert answer you'll need to create a free account at Brainly

distance d is directly proportional to weight w so, d = k * w (where k is some constant you don't know yet)
when d = 23, w = 3 so, 23 = k * 3 which means k = 23/3
now, you have to find d when w = 5 d = k * w = 23/3 * 5

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

another way of thinking about it: 3 kg stretches the spring by 23 cm so 5 kg will stretch it even more
3 kg stretches it by 23 cm in other words, each kg stretches it by 23/3 cm so, 5 kg will stretch it 5 times that much = 5 * 23/3
ok thanks

Not the answer you are looking for?

Search for more explanations.

Ask your own question