anonymous
  • anonymous
Hooke's Law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. If the distance is 23 cm when the weight is 3 kg, what is the distance when the weight is 5 kg? I need the answer badly and I do not understand how to do the problem.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
ok quic anser is 25
anonymous
  • anonymous
that answer is incorrect
anonymous
  • anonymous
its 38

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Thats not correct either
ashwinram
  • ashwinram
3 kg stretches the spring by 23 cm so, each kg stretches it by 23/3 cm
ashwinram
  • ashwinram
so, 5 kg will stretch it 5 times that much 5 * 23/3 = 38.33
anonymous
  • anonymous
naw the correct answer was 115/3

Looking for something else?

Not the answer you are looking for? Search for more explanations.