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anonymous

  • 5 years ago

F(x) is a polynomial of 8 degree f(K)=1/k K=1,2,3,4,5,6,7,8,9 find F(10)?

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  1. anonymous
    • 5 years ago
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    Replace K with 10 f(10)=1/10

  2. anonymous
    • 5 years ago
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    nopes its not that

  3. anonymous
    • 5 years ago
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    Is that the whole question?

  4. anonymous
    • 5 years ago
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    yup !!

  5. anonymous
    • 5 years ago
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    Jai, I think what you're being asked to do is recognize this: You are told you have a polynomial of degree 8 which you have to find. So you have\[f(x)=a_8x^8+a_7x^7+...+a_1x+a_0\]Being asked to find the polynomial is the same as saying, "Find the coefficients above." You're told that, at the points x=1 to 9, the function f(x) is equal to 1/x; that is, \[\frac{1}{x}=a_8x^8+a_7x^7+...+a_1x+a_0\]for x=1,2,...,9. So,

  6. anonymous
    • 5 years ago
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    for x=1,\[\frac{1}{1}=1=a_8(1)^8+a_7(1)^7+...+a_1(1)+a_0\]that is,\[1=a_8+a_7+...+a_1+a_0\]This is one (linear) equation. You repeat the process for the other eight numbers and you'll have nine linear equations in nine unknowns. Those unknowns are the coefficients. You can solve this system exactly for those coefficients. You'll then have the polynomial. Once you have the polynomial, you can use it to calculate f(10).

  7. anonymous
    • 5 years ago
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    It's turgid algebra. If you don't have to show how you've solved for the coefficients, I would demonstrate that you can set the problem up, and illustrate how you solve it (e.g. matrices). Then look for an online matrix calculator to solve the system. Doing it by hand will take a long time, and there's so much room for error.

  8. anonymous
    • 5 years ago
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    Does this help?

  9. anonymous
    • 5 years ago
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    yes, thanks

  10. anonymous
    • 5 years ago
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    No probs.

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