## anonymous 5 years ago inscribed in an equalateral riangle is a circle. the height of the circle is 12 times the square root of 3. what is the circumference?

1. anonymous

okay, let's write the given:$h = 12\sqrt{?}$ the height is actually the diameter of the circle so : $D = h = 12\sqrt{3}$ So you can find R : $R = D/2 = 12\sqrt{3}/2 = 6\sqrt{3}$ substitute R in the general equation of the circumference which is: $C = 2\pi r =12\sqrt{3}\pi$ Correct me if I'm wrong ^_^

2. anonymous

h= 12sqrt(3) * my bad :)

3. anonymous

the circumference of the circle is = $2\prod_{}^{}r$ =2 * pi * ($12\sqrt{3} / 2$

4. anonymous

= 2 * pi * 6 sqrt(3)

5. anonymous

^_^

6. anonymous

7. anonymous

did u get it?

8. anonymous

lol that's what I got, he hopefully got it now ^_^