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anonymous
 5 years ago
solve diff eq sinxcosx*dy\dx=y+sinx
anonymous
 5 years ago
solve diff eq sinxcosx*dy\dx=y+sinx

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0take dx to the othr side

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dy\dx = y+sinx \ sin x cos x .... sinxcosx = it would look like this.. dy\dx = y + sin x \ sinxcosx =0 .. rewrite it to.. dy\dy  y\1\2 sin2x = sinx \sinxcosx dy\dy  y\1\2 sin2x = 1\cosx .. hope i did nt to any wrongs..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmmm...yeah its fine till here...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then, you need to find the Integration factor.. and U\[U \times Y \int\limits_{}^{} U \times 1\div cosx... Their .. U = e ^{\int\limits_{}^{} 1\div (1\div 2 \times \sin (2x))}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sry i forgott i Minus before U=e∫1÷(1÷2×sin(2x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey i think the person who asked the question is not here

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Have u done the this?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that makes it \[e ^{\int\limits_{}^{} 2/sin2x}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And that Integral, i am not sure of..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can take, u =sin 2x and solve

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0aha, so u mean that e∫2/sin2x = sin2x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no, not that 'U', lets take.. say p=sin2x, so that , int(1/p) = log p = log (sin 2x) ...got it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0noe it gives e^ (log (sin 2x))

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{} 1\div p =\ln p\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what about the inner derivata? 2x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that 2 in the denominator o f '1/2' goes to the numerator as '2'

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Found it. ∫ 1/sin(2x) dx = ∫ csc(2x) dx. Let u = 2x <==> du = 2 dx. Then, the integral becomes: 1/2 ∫ csc(u) du = lncot(u) + csc(u)/2+ C = lncot(2x) + csc(2x)/2 + C. <== ANSWER

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0finally, got the answer huh:)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha.. yeah.. long time ago, with math..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Need to refresh my memory!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ha ha ..anyways you found it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@nabaz&thinker thnxs for the help buddies i am getting the same ! but the ans is given to b \[y cotx=c+lntan \left( x/2 \right)\] is it the same?
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