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anonymous

  • 5 years ago

A triangle drrawn with angles of 40 degrees at the top and 65 degrees on the far right with a measurement of 72 on one side(right side line) sits next too a triangle of a 40 degree angle at the top with a line measurement of 52 on the left side and 45 line measurement on the right side. What would the length of all the missing sides and missing angles be?

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  1. anonymous
    • 5 years ago
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    In the first triangle the last angle is given by 180-40-65=...

  2. amistre64
    • 5 years ago
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    you can use a mixture of the law of cosine and the law of sines to determine these...

  3. amistre64
    • 5 years ago
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    2nd triangle: a=52; C=40 b=45 Find B (bottom left angle), A (bottom right angle), and c (bottom line) c^2 = a^2 + b^2 -2ab cosC c^2 = 52^2 + 45^2 -2(52)(45)(cos(40)) c^2 =

  4. amistre64
    • 5 years ago
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    c^2 = 4729 - 4680(cos(40))

  5. amistre64
    • 5 years ago
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    c^2 = 1143.9120062031827952528023954006 c = 33.8218 if i did it right....

  6. amistre64
    • 5 years ago
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    sinA sinB sinC ---- = ---- = ---- a b c

  7. anonymous
    • 5 years ago
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    Thank you very much

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