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anonymous
 5 years ago
A container with a square base, vertical sides and an open top is to be made from 1200ft squared of material. find the dimensions of the container with the greatest volume.
anonymous
 5 years ago
A container with a square base, vertical sides and an open top is to be made from 1200ft squared of material. find the dimensions of the container with the greatest volume.

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know if all 1200 ft^2 of material is to be used? or is it one of those"cut out the corners" kind of problems?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the container, if all material is to be used would have a surface area of: 4(side area) + (base area) = 1200

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you just need the sum of the areas of the surfaces to add up to 1200sqft. so (area of base)+4×(area of one side) = 1200 sqft

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.04xy + x^2 = 1200 , does that sound right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0solve for one variable in terms of the other, plug it into the volume equation, and derive :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0and dont let the "hero" title fool ya.... I am after all an idiot in disguise :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0V = (x^2/4x)(1200x^2)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0V = (1/4) (1200x^3) if I did it right...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0dV = (1/4)(1200  3x^2) maybe make that equal to 0 to get the critical numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, I misread the problem.. yes, put y in terms of x, y = (1200 x^2)/4x, then substitute into volume V = x^2 y = x^2 (1200 x^2)/4x = x(1200x^2)/4 = x(300(x^2)/4), then find the maximum volume

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you've taken calculus you can do that my finding the zeros of the derivative, otherwise I think you'll have to test sample values and just find the x that yields the greatest V

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x=20 i think plug that back in to your "y" equation to ge the value for y

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y = (1200 20^2)/4(20) y = (1200  400)/ 80 y = 800/80 = 80/8 = 10/1 y = 10 and x = 20 if i did it all correctly

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0determine if 20x20x10 is greater than 10x10x20 and youve got your answer

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0or.... ignore that last comment...its probably my stupidity talking :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.020x20 for the base, and 10 high fits all the requirements

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0but, do you see how we got it?
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