anonymous
  • anonymous
Can someone explain the obnoxious constant that shows up when solving integrals? Is this necessary when you have defined bounds?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
When you take the derivative of a function with a constant (for example, 3x + 5), the constant disappears. When you take the integral of 3, you end up with 3x+c - in order to account for any constant that may have disappeared from the original function. And no, the constant is not necessary when you have a definite integral, because you end up saying +c - c. :)
amistre64
  • amistre64
a definite integral is the result of defined bounds i think
amistre64
  • amistre64
an indefinite integral is boundless (+C).... if I recall correctly

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anonymous
  • anonymous
thank you - that explains everything
anonymous
  • anonymous
Glad to help.

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