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anonymous

  • 5 years ago

Can someone explain the obnoxious constant that shows up when solving integrals? Is this necessary when you have defined bounds?

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  1. anonymous
    • 5 years ago
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    When you take the derivative of a function with a constant (for example, 3x + 5), the constant disappears. When you take the integral of 3, you end up with 3x+c - in order to account for any constant that may have disappeared from the original function. And no, the constant is not necessary when you have a definite integral, because you end up saying +c - c. :)

  2. amistre64
    • 5 years ago
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    a definite integral is the result of defined bounds i think

  3. amistre64
    • 5 years ago
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    an indefinite integral is boundless (+C).... if I recall correctly

  4. anonymous
    • 5 years ago
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    thank you - that explains everything

  5. anonymous
    • 5 years ago
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    Glad to help.

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