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anonymous
 5 years ago
What would you calculate to come up with the AU portion of the following...
1pc = 3.26ly = 2.06 × 10^5 AU where 1ly = 9.46 × 10^15m
I was understanding the lightyear calculations fine, but I am not able to come up with 2.06 × 10^5 AU from 3.26ly
Thank You.
anonymous
 5 years ago
What would you calculate to come up with the AU portion of the following... 1pc = 3.26ly = 2.06 × 10^5 AU where 1ly = 9.46 × 10^15m I was understanding the lightyear calculations fine, but I am not able to come up with 2.06 × 10^5 AU from 3.26ly Thank You.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The simplest definition of an AU (though not strictly correct) is the semimajor axis of the earth's orbit around the sun  149 597 870 700m. to convert ly to AU's: 3.26 ly * (3 x 10^8m/s * 1 yr)/ly * 365.25d/yr * 24 h/d * 3600s/h * 1AU/149597870700m This is just a "chainlink" conversion

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Stan, thank you for the reply. I understand all of that except where you got (3 x 10^8m/s * 1 yr) from. What does that represent? Thanks.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0he distance light travels in a year is its speed times the time (d = v*t). Speed is 3 x 10^8 m/s, time is 1 year
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