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anonymous
 5 years ago
If you have a triangle with angles of 30, 60 and 90 with a side of 12, what would the other two sides be?
anonymous
 5 years ago
If you have a triangle with angles of 30, 60 and 90 with a side of 12, what would the other two sides be?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0side opposite 30 = 12? side opposite 60 = 12? or side opposite 90 = 12? these are 3 different results....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops I wrote it wrong, the side opposite is 21

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can use the law of of sines or cosines to get the answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0law of sines is \[sineA/a=sinb/b\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[Sin 30/21=sine 60/x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cross multiply sin 30 x=(21)(sin60)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Use a calculator to figure out the sines .05x = (21)(0.86602540378444) x=9.09326673973662

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the side opposite 60 deg. is 9.09326673973662

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if you can visualize the 306090 triangle (or draw it); then things get simpler as well; the slanted part(hypotenuse) has a normal value = 2 the leg opp. 60 has a normal value = sqrt(3) the leg opp. 30 has a normal value = 1 since opp 30 = 21 in your problem, then 1x = 21..x = 21 we want to multiply all these "normal" values by 21 to get the measurements of the other 2 sides: slant = 2(21) = 42 and leg opp 60 = 21sqrt(3) or 36.37

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I messed up in the last part of the algebra
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