anonymous
  • anonymous
3root9x-1 =2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Dont understand.. do you mean \[\sqrt[3]{9x-1} =2\]
anonymous
  • anonymous
yes, i just don't know how you enter it that way
anonymous
  • anonymous
Equation, ... if you look down..

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anonymous
  • anonymous
It become \[9x-1=2^{3}\]
anonymous
  • anonymous
I see that
anonymous
  • anonymous
\[2^{3}= 8 .\] \[8=9x-1\]
anonymous
  • anonymous
Solve X
anonymous
  • anonymous
ok, so x=1?
anonymous
  • anonymous
yes
anonymous
  • anonymous
ok, that was easy!!
anonymous
  • anonymous
yepp.. :)
anonymous
  • anonymous
Do you know how to rewrite using radical notation?
anonymous
  • anonymous
i can give it a try
anonymous
  • anonymous
I have (16 little 3/2)little 2/6 hard to write the little numbers!!
anonymous
  • anonymous
aha..
anonymous
  • anonymous
if you mean \[(3\div2)^{16}\]
anonymous
  • anonymous
no 16 is in parenthesis with a little 3/2 off to the right then there is a little 2/6 to the right of that
anonymous
  • anonymous
aha..
anonymous
  • anonymous
Would you like me to caluc it?
anonymous
  • anonymous
the directions say to write using radical notation
anonymous
  • anonymous
You just mutilpy, 3\2 with 2\6
anonymous
  • anonymous
and then you get a notation 1\2 over 16 = 4
anonymous
  • anonymous
if their is a notation over another notation you can mutiply with each other..
anonymous
  • anonymous
ok, so it will be 2root4 then??
anonymous
  • anonymous
1\2 root 4
anonymous
  • anonymous
3\2 x 2\6 = 6\12 rewrite to 1\2 by dividing with 6 on both side
anonymous
  • anonymous
Ok, I think I got it!! Thanks :)
anonymous
  • anonymous
Your welcome!

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