anonymous
  • anonymous
How do I solve this for x?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
\[1/x = 3/(x+2) - 2/(x - 3)\]
anonymous
  • anonymous
Start with getting the same nr under the lines..
anonymous
  • anonymous
so you can add them with each other..

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anonymous
  • anonymous
\[1/x=3/(x+2)−2/(x−3)\] \[1(x-2)(x-3)/x(x-3)(x-2)=3x(x-3)/(x+2)(x-3)x−2x(x-2)/(x−3)(x-2)x\]
anonymous
  • anonymous
start by multiplying by the least common denominator x(x+2)(x-3), you will get: \[(x+2)(x-3)=3x(x-3)-2x(x+2)\] which is a quadratic equation that can be easily solved
amistre64
  • amistre64
ouch, that hurts the synapses in me brain.... pencil and paper...much nicer...
anonymous
  • anonymous
oh, it should be (x+2)
anonymous
  • anonymous
\[x^2-x-6=3x^2-9x-2x^2-4x \implies 12x=6 \implies x+1/2\]
anonymous
  • anonymous
x=1/2**
anonymous
  • anonymous
yepp,

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