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anonymous

  • 5 years ago

I'm having a problem with solving this double integral...can someone help me?

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  1. anonymous
    • 5 years ago
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    Hard to tell if we can't see it ;)

  2. anonymous
    • 5 years ago
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    ok there's no way i can put it up like im seeing it because there's integral sign but i'll try my best...

  3. anonymous
    • 5 years ago
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    integral 0-2 (integral 0-x/2 5(e)^(x)^2 dy dx)...help me please

  4. myininaya
    • 5 years ago
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    first we integrate inside ignore the outside for right now

  5. myininaya
    • 5 years ago
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    since we are integrating with repsect to y we treat everything thats not y ish as a constant

  6. anonymous
    • 5 years ago
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    i under stand that. There's no y so I dont understand if i just put a y in there?

  7. myininaya
    • 5 years ago
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    what? so you are saying you don't see the inside being 5ye^x^2?

  8. anonymous
    • 5 years ago
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    no, there's not a y in the whole problem

  9. myininaya
    • 5 years ago
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    whats the antiderivative of 5 with repect to x

  10. anonymous
    • 5 years ago
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    0

  11. myininaya
    • 5 years ago
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    no

  12. anonymous
    • 5 years ago
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    5x?

  13. myininaya
    • 5 years ago
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    its 5x since the derivative of 5x is 5

  14. myininaya
    • 5 years ago
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    so now you understand how we got 5ye^x^2 for inner integral (we haven't used upper and lower limit yet for inner integral)

  15. anonymous
    • 5 years ago
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    ok so you added a y because we were doing respect to y?

  16. myininaya
    • 5 years ago
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    yes and the derivative of 5ye^x^2 with respect to y will be 5e^x^2

  17. myininaya
    • 5 years ago
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    so the inside integral becomes (5(x/2)e^x^2-0)

  18. myininaya
    • 5 years ago
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    now we have the outside integral that we integrating with respect to x

  19. myininaya
    • 5 years ago
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    use a substitution for x^2

  20. anonymous
    • 5 years ago
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    du/2=x

  21. myininaya
    • 5 years ago
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    du/2=x dx yes

  22. myininaya
    • 5 years ago
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    dont forget to put the limits in u terms

  23. myininaya
    • 5 years ago
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    so the upper limit will be 4 and the lower limit will be 0

  24. myininaya
    • 5 years ago
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    so we have int((5/4) *e^u, u=0..4)=(5/4)e^u, u=0..4= (5/4)e^4-(5/4)e^0=(5/4)e^4

  25. myininaya
    • 5 years ago
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    -1

  26. myininaya
    • 5 years ago
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    i forgot about the minus 1 sorry

  27. myininaya
    • 5 years ago
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    e^0=1

  28. anonymous
    • 5 years ago
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    thank you very much

  29. myininaya
    • 5 years ago
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    np don't be afraid to ask any other questions or this one over if you want

  30. anonymous
    • 5 years ago
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    is this a 24 hour website?

  31. anonymous
    • 5 years ago
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    on this problem, and when doing substitution is it always required to put the limits in u terms?

  32. myininaya
    • 5 years ago
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    i don't know. people come and go as they please. the tutors work whenever they want because we don't work for the website we work because we think its fun lol

  33. myininaya
    • 5 years ago
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    if you don't put the limits in terms of u, you have to change it back to x and use the limits for x

  34. anonymous
    • 5 years ago
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    is there any way you can explain that?

  35. myininaya
    • 5 years ago
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    its the same thing

  36. myininaya
    • 5 years ago
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    lets do an example...

  37. anonymous
    • 5 years ago
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    this seems like it's going to be a really hard problem

  38. myininaya
    • 5 years ago
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    no its not hard i'm just busy doing something else at sametime

  39. myininaya
    • 5 years ago
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    pretend we have int(5x,x=0..1)

  40. myininaya
    • 5 years ago
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    if we integrate this normal way we get 5x^2/2 x=0..1 = 5/2

  41. myininaya
    • 5 years ago
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    we could also do u substitution if we just wanted to for fun so let u=5x

  42. myininaya
    • 5 years ago
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    du=5dx => du/5=dx

  43. anonymous
    • 5 years ago
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    ok

  44. myininaya
    • 5 years ago
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    so we get int(1/5 (u), u=blah blah) =1/5 *u^2/2 let's change this back to x so we will have 1/5*((5x))^2/2 x=0..1 but we could have already done the 5x if we had used u=5x

  45. anonymous
    • 5 years ago
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    ok

  46. anonymous
    • 5 years ago
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    is it ok to ask another question or should i just retype it on the "ask a question"? you seem to really know your stuff thats why im asking

  47. myininaya
    • 5 years ago
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    that didn't answer it?

  48. anonymous
    • 5 years ago
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    i mean i have another question.

  49. myininaya
    • 5 years ago
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    oh lol yeah I have to do something. I'm fixing to have to move a mattress

  50. anonymous
    • 5 years ago
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    ok, thanks for all your help. hope you make lots of money with your math skill one day

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