anonymous
  • anonymous
int(int(6xy^3 x=y..1) y=0..1) dxdy
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Is your problem\[\int\limits_{0}^{1}\int\limits_{y}^{1}6xy^3dxdy\]?
anonymous
  • anonymous
yes it is
anonymous
  • anonymous
Okay, just give me a sec to do something non-mathematical. I can help you.

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anonymous
  • anonymous
ok, cool. i got 1/4, can you tell me if that's right? when ever you're done though
anonymous
  • anonymous
Okay...I scratched it out and got 1/4 too. You know what you're doing.
anonymous
  • anonymous
yeah but i'm have a problem with another one...is it ok to ask you one more?
anonymous
  • anonymous
sure
anonymous
  • anonymous
ok it's another double...int(int(5sin(x+y) x=0..pi/2) y=0..pi/2) dxdy
anonymous
  • anonymous
I got 10. Is that what you got?
anonymous
  • anonymous
i keep getting stuck...this is the third time trying to do it again
anonymous
  • anonymous
It might be easier for me to scan what I did and attach then write it out...have a look through if and ask questions.
anonymous
  • anonymous
perfect thanks
anonymous
  • anonymous
Everything under the red line.
1 Attachment
anonymous
  • anonymous
sorry im comparing right now...
anonymous
  • anonymous
That's okay. I'll be online for a while. Just post when you're ready. If I don't respond 'immediately', I'm away from the computer.
anonymous
  • anonymous
ok i see it
anonymous
  • anonymous
I think you're getting trapped by not just accepting that the other variable is just a constant when you integrate over the other in a double integral.
anonymous
  • anonymous
your fourth step is different from mine. i dont understand how you went from cos (pi/2 + y) to it becoming sin y
anonymous
  • anonymous
We get very used to thinking of x and y as things that vary, rather than stand still.
anonymous
  • anonymous
You can use the double angle formula. You'll see I did that expansion in the top right corner (under the red line).
anonymous
  • anonymous
\[\cos(\frac{\pi}{2}+y)=\cos \frac{\pi}{2}\cos y - \sin \frac{\pi}{2}\sin y\]\[=0 \times \cos y + (- 1) \times \sin y=-\sin y\]
anonymous
  • anonymous
thank you so much. i would have never remembered that rule
anonymous
  • anonymous
no probs.
anonymous
  • anonymous
when you're done and you're satisfied, it'd be great if you could click the 'become a fan' link :)
anonymous
  • anonymous
just did it
anonymous
  • anonymous
cheers
anonymous
  • anonymous
so you're getting the same answer?
anonymous
  • anonymous
yes, after remembering the rule it all made sense
anonymous
  • anonymous
good.

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