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anonymous
 5 years ago
Change the Cartesian Integral into an equivalent polar integral then evaluate: (int(int(dydx)) from 1 to 1 and 0 to sqrt(1x^2)
anonymous
 5 years ago
Change the Cartesian Integral into an equivalent polar integral then evaluate: (int(int(dydx)) from 1 to 1 and 0 to sqrt(1x^2)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How'd you do it? If I may

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0YOu have to graph the boundaries then find the new boundaries: 0 to pi/2 and 0 to 1. Then you use the equation int(int(rdrdtheta) which = pi/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0limits for r are 0 to 1, theta 0 to pi

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got 0 to pi /2 because its y...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}{}\int\limits_{}{}dxdy=\int\limits_{}{}\int\limits_{}{}\frac{\partial J(x,y)}{\partial (r, \theta)}dr d \theta=\int\limits_{}{}\int\limits_{}{}r dr d \theta\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Integrate out r from 0 to 1, then theta from 0 to pi.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You get \[\frac{\pi}{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohh i see that thanks

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0welcome. i stopped on your question and went for a shower  thought someone was taking it.
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