## anonymous 5 years ago Change the Cartesian Integral into an equivalent polar integral then evaluate: (int(int(dydx)) from -1 to 1 and 0 to sqrt(1-x^2)

1. anonymous

nvm got it...

2. anonymous

How'd you do it? If I may

3. anonymous

YOu have to graph the boundaries then find the new boundaries: 0 to pi/2 and 0 to 1. Then you use the equation int(int(rdrdtheta) which = pi/2

4. anonymous

limits for r are 0 to 1, theta 0 to pi

5. anonymous

I got 0 to pi /2 because its y...

6. anonymous

$\int\limits_{}{}\int\limits_{}{}dxdy=\int\limits_{}{}\int\limits_{}{}|\frac{\partial J(x,y)}{\partial (r, \theta)}|dr d \theta=\int\limits_{}{}\int\limits_{}{}r dr d \theta$

7. anonymous

Integrate out r from 0 to 1, then theta from 0 to pi.

8. anonymous

You get $\frac{\pi}{2}$

9. anonymous

ohh i see that thanks

10. anonymous

welcome. i stopped on your question and went for a shower - thought someone was taking it.