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anonymous

  • 5 years ago

integration

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  1. anonymous
    • 5 years ago
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    \[\int\limits{4x(1-4x)^{3}}\]

  2. anonymous
    • 5 years ago
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    This one's a little less intuitive. Let u = 1-4x. Then, you end up with ∫ (1-u)*u^3 du, and you can expand after that - at the end, just plug in the value of u and you're finished.

  3. anonymous
    • 5 years ago
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    I had u=1-4x but i dont understand how you got (1-u) x u^3 du

  4. anonymous
    • 5 years ago
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    Alright, so we have u = 1-4x, which subs into the integrand as u^3. Then, we have 4x = 1-u, so we can put (1-u) into the equation instead of 4x. Then, we know that du = -4 dx, so dx = -du/4, which you can plug into the integrand as well. I think in total you get -1/4 * ∫(1-u)*u^3 du

  5. anonymous
    • 5 years ago
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    thats right! thanks you. i finally understand

  6. anonymous
    • 5 years ago
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    Glad to help. :)

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