## anonymous 5 years ago The position of an object is given by p(t)=3t^2-2t+9 what is the average velocity of the object from t=-1 to 5=1?

The average of a function f(x) over an interval [a,b] is,$\frac{1}{b-a}\int\limits_{a}^{b}f(x) dx$Here, $\frac{1}{1-(-1)}\int\limits_{-1}^{1}3t^2-2t+9dt \rightarrow \frac{1}{2}[t^3-t^2+9t]_{-1}^1$$=\frac{1}{2}(9-(-11))=10$