anonymous
  • anonymous
how do i solve 3/ -4k^2- 5sqrt k^4?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
is the equation: (3/-4k^2) - 5 sqrt(k^4) ?
anonymous
  • anonymous
no its 3 over the entire -4k^2- 5sqrt k^4.
amistre64
  • amistre64
3/ (4k^2 -5 sqrt(k^4)) then?

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amistre64
  • amistre64
with the (-)
anonymous
  • anonymous
yes
amistre64
  • amistre64
lets work on that "sqrt(k^4)" and see if we cant "undo" it..ok? what do you know of square roots and exponents?
anonymous
  • anonymous
they r opposites of each other. you can use one to undo the other.
amistre64
  • amistre64
good... how can we re-write sqrt(k^4) so that we can "undo" it? sqrt(k^2 k^2) is a start; and everything with a "^2" can be taken out right? So, kk can come out, which = k^2 do you agree?
anonymous
  • anonymous
yes
amistre64
  • amistre64
Then lets see how this helps us with the rest of the denominator: 4k^2 -5k^2 what can we do with this?
amistre64
  • amistre64
i keep forgetting the (-). -4k^2 -5k^2
anonymous
  • anonymous
its cool. we can take out k^2 rite?
amistre64
  • amistre64
yes, you are right... k^2(-4-5) = -9k^2 right?
anonymous
  • anonymous
yea
amistre64
  • amistre64
now lets look how this helps us with the rest of it: 3/(-9k^2) do you see anything else we can do to this?
amistre64
  • amistre64
3 ------ -9 k^2
anonymous
  • anonymous
-1 ----- 3k^s ?
amistre64
  • amistre64
yes, exactly :) even tho the ^s is a typo.... I will let it slide :)
anonymous
  • anonymous
thank you so much!
amistre64
  • amistre64
youre welcome...

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