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anonymous

  • 5 years ago

2/3x+4/3x=-2/3

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  1. anonymous
    • 5 years ago
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    alright, let's simplify it in a better form ^_^:\[2/3x(2x+4) = -2/3\] cross mulitply now: \[-6x(3x + 4)= 6\] \[-6x(3x+4) - 6 = 0\]\] \[-6(3x^2 + 4x +1 ) = 0\] \[-6(3x + 1)(x + 1) = 0\] so your zeros are : x = -1/3 and x= -1 ^_^

  2. anonymous
    • 5 years ago
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    is it clear now? :)

  3. anonymous
    • 5 years ago
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    so the answer is 0

  4. anonymous
    • 5 years ago
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    no lol, you want to find x right?

  5. anonymous
    • 5 years ago
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    yes sorry about its early

  6. anonymous
    • 5 years ago
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    np ^_^ so you'll have 2 sets of x equations which are: 3x + 1 =0 and x+ 1 =0 x = -1/3 and x = -1 therefore your x's are : x = -1/3 and x = -1

  7. anonymous
    • 5 years ago
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    oh ok got it ... thank you!

  8. anonymous
    • 5 years ago
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    you'r welcome :)

  9. anonymous
    • 5 years ago
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    you're* ^^"

  10. anonymous
    • 5 years ago
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    can't I have one day with no typos =-=

  11. anonymous
    • 5 years ago
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    sstarica, you are such a good person that I cant even believe it, I mean, you spend your precious time helping others

  12. anonymous
    • 5 years ago
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    thank you andy, I appreciate such kind words :)

  13. anonymous
    • 5 years ago
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    sstarica do have time for one more problem?

  14. anonymous
    • 5 years ago
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    sure np ^_^

  15. anonymous
    • 5 years ago
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    0.06(z-300)+0.05z=0.07z-205

  16. anonymous
    • 5 years ago
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    First, let's multiply using the distributive law :\[0.06z - 18+0.05z -0.07z + 205 = 0\] Solve for z and you'll get: \[0.04z = -187\] \[z = -187/0.04 = -4675\] so z = -4675 ^_^

  17. anonymous
    • 5 years ago
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    how did u get the 187

  18. anonymous
    • 5 years ago
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    you subtract 205 from 18: 205 - 18 = 187 move it to the other side to get z alone and it'll be -187 ^_^

  19. anonymous
    • 5 years ago
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    ok got it

  20. anonymous
    • 5 years ago
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    great :)

  21. anonymous
    • 5 years ago
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    thank you , you are really good at this ..thanks again

  22. anonymous
    • 5 years ago
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    it's my pleasure dear ^_^ good luck

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